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Voltage Drop Calculator: Formula and Example

Learn how to estimate single-phase and three-phase cable voltage drop, with worked copper cable examples.

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Voltage drop estimates

What does voltage drop mean?

Voltage drop is the difference between the supply voltage and the voltage at a load due to impedance in the circuit conductors.

Simplified formula

For single-phase two-wire circuits: ΔU ≈ 2 × I × ρ × L / A. For balanced three-phase circuits: ΔU ≈ √3 × I × ρ × L / A. I is current in amperes, ρ is resistivity in Ω·mm²/m, L is one-way cable length in metres, and A is conductor area in mm².

Worked example

A single-phase circuit with 20 A, 50 m one-way copper cable, and 6 mm² cross-section, using copper resistivity 0.01724 Ω·mm²/m at 20°C: ΔU ≈ 2 × 20 × 0.01724 × 50 / 6 = 5.75 V, or about 2.50% of 230 V.

Important limitations

This is a resistive estimate at 20°C, not a final cable-sizing or regulatory-compliance check. Real voltage drop depends on operating temperature, reactance, power factor, cable construction and circuit configuration. The load-end voltage approximation may not be physically meaningful if the estimated drop exceeds the supply voltage.

Related tools

Voltage drop · Three-phase power · Ohm’s law

Educational estimates only. Verify calculations independently before using them in electrical work.